[laksh_khamesra]

This code i have made to take out age of the user(the date in the mktime is just for testing). But many problems are occurring like if the user was born on 2nd of a month today is 1st of a month then the date comes in minus (-) which makes it too confusing... After all, i m completely stuck & confused. Please tell how to take out users age.

PHP Code:

$td = mktime(0,0,0,05,24,1991);
$td1 = time();

$aa = date("Y", $td);
$bb = date("Y", $td1);
$age = $bb - $aa;

$cc = date("m", $td);
$dd = date("m", $td1);
$month = $dd - $cc;

$ee = date("d", $td);
$ff = date("d", $td1);
$days = $ff - $ee;

echo "$age years, $month months and $days days"; 


[Cborrow]

Try this.

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[datahound]

Did not work when I tried it, sorry.

[datahound]

11 months out.

[Cborrow]

Yeah, I'm not sure what it is but mktime returns the month as 12. If I change the day to 09 the month changes to 11. Anthing over Aug 9th renders the month as 12.

Edit: Find a function online that seems to do what you want.

time since [date] [php] [time] [since]

[feha]

try this
PHP Get Age Function | Trevor Davis

My-PHP.tk ••• Your Free PHP Resource! •••

or google for "age php function"

[combatsheep]

PHP Code:

<?php
$date = strtotime("11/04/1984"); // could be your sql result or timestamp

$day = date('jS',$date);
$month = date('F',$date);
$year = date('Y',$date);


echo "My birthdate is the $day of $month , $year";
?>

Remember date() accepts US dates by default so 4/11/1984 in US is 11/04/1984.

look at php.net/date for formatting options.

[feha]

@combatsheep
I think he wanted to calculate the age on given date ...
not date conversion