[chris_bcn]

I'm desperately trying to learn php as I go along

I've been trawling through php.net for a couple of weeks and trying to cram as much php into my head as possible.

And so, my question - I'm trying to use getimagesize() function

I'm trying to get an image and it's width and height returned.

I define $brandingimg in each document, and want to have the image and the width and the height returned. I also want a way of putting alt and/or title text - I'm guess I can just put a variable $alt in there and define it in each page.

<?php
$image = "/i/$brandingimg";
$size = getimagesize("$image");
$height = $size[1];
$width = $size[0];
echo "<img src=\"$image\" height=\"$height\" width=\"$width\" />";
?>

The image is returned fine, but the height and width are empty.

Any help would be great

[smallbeer]

have you tried without quoting the $image variable?

$size = getimagesize($image);

[chris_bcn]

cheers for the idea - that didn't make any difference though unfortunately

[smallbeer]

try using an absolute file path instead then.

[dtrenz]

yes, try absolute path, or try "i/$brandingimg" instead of "/i/$brandingimg"

[datahound]

<?php
$size = getimagesize("/i/".$brandingimg);
$image = "/i/$brandingimg";
$height = $size[1];
$width = $size[0];
echo "<img src=\"$image\" height=\"$height\" width=\"$width\" />";
?>

Does this work?

[datahound]

or

<?php
$size = getimagesize("/i/$brandingimg");
$image = "/i/$brandingimg";
$height = $size[1];
$width = $size[0];
echo "<img src=\"$image\" height=\"$height\" width=\"$width\" />";
?>

[dtrenz]

Originally Posted by datahound

$size = getimagesize("/i/".$brandingimg);

oh yeah!!! i think variables are only evaluated in double-quotes in an echo statement. so this should fix it. nice catch.

[chris_bcn]

cheers all - seems to be working a treat now