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combatsheep · 15-09-2008, 09:03

PHP Code:


		
			
<?php

$date = strtotime("11/04/1984"); // could be your sql result or timestamp



$day = date('jS',$date);

$month = date('F',$date);

$year = date('Y',$date);





echo "My birthdate is the $day of $month , $year";

?>

Remember date() accepts US dates by default so 4/11/1984 in US is 11/04/1984.

look at php.net/date for formatting options.

15-09-2008, 09:03	#7 (permalink)
combatsheep trained to kill Join Date: Apr 2008 Location: Liverpool, UK Posts: 134	PHP Code: `<?php $date = strtotime("11/04/1984"); // could be your sql result or timestamp $day = date('jS',$date); $month = date('F',$date); $year = date('Y',$date); echo "My birthdate is the $day of $month , $year"; ?>` Remember date() accepts US dates by default so 4/11/1984 in US is 11/04/1984. look at php.net/date for formatting options.